AIR MATH

Math Question

Prove: The square of a number that is one more than a multiple of 3 is also one more than a multiple of \( 3 . \)
\[
\begin{aligned}
(3 n+1)^{2} &=[?] n^{2}+[] n+[] \\
&=[]\left([] n^{2}+[] n\right)+[] \\
&=1 \text { more than a multiple of } 3
\end{aligned}
\]

Solution

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