AIR MATH

Math Question

10. A ball is launched from a 74.48-meter tall platform. The equation for the ball's height \( h \) at time \( t \) seconds after launch is \( h(t)= \) \( -4.9 t^{2}+27.44 t+74.48 \), where \( h \) is in meters. At what time does the ball achieve its maximum height?

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