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Math Question

Use one of the other Rhombus theorems to complete the proof that if the diagonals of a parallelogram are perpendicular, then the parallelogram is a rhombus. Given: \( P Q R S \) is a parallelogram. \( \overline{P R} \perp \overline{Q S} \) Prove: \( P Q R S \) is a rhombus. Part 1 out of 7 \begin{tabular}{|l|l|} \hline Statements & Reasons \\ \hline 1. PQRS is a parallelogram. & 1. Given \\ \hline 2. \( \overline{P T} \propto \square \) & 2. Diagonals of a parallelogram bisect each other. \\ \hline \end{tabular} Check Next

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