AIR MATH

Math Question

Which table represents viable solutions for \( y=5 x \), where \( x \) is the number of tickets sold for the school play and \( y \) is the amount of money collected for the tickets?
School Play Tickets
\begin{tabular}{|c|c|}
\hline Tickets \( (x) \) & Money Collected \( (y) \) \\
\hline\( -100 \) & \( -500 \) \\
\hline\( -25 \) & \( -125 \) \\
\hline 40 & 250 \\
\hline 600 & 3,000 \\
\hline
\end{tabular}
School Play Tickets
\begin{tabular}{|c|c|}
\hline Tickets \( (x) \) & Money Collected \( (y) \) \\
\hline\( -20 \) & \( -100 \) \\
\hline 20 & 100 \\
\hline 100 & 500 \\
\hline 109 & 545 \\
\hline
\end{tabular}
School Play Tickets
\begin{tabular}{|c|c|}
\hline Tickets \( (x) \) & Money Collected \( (y) \) \\
\hline 0 & 0 \\
\hline 10 & 50 \\
\hline 51 & 255 \\
\hline 400 & 2,000 \\
\hline
\end{tabular}
School Play Tickets
\begin{tabular}{|c|c|}
\hline Tickets \( (x) \) & Money Collected \( (y) \) \\
\hline 5 & 25 \\
\hline 65 & 350 \\
\hline
\end{tabular}

Solution

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