AIR MATH

Math Question

e tables represert two linear functions in a system. \begin{tabular}{|c|c|} \hline\( x \) & \( y \) \\ \hline\( -6 \) & \( -22 \) \\ \hline\( -3 \) & \( -10 \) \\ \hline 0 & 2 \\ \hline 3 & 14 \\ \hline \end{tabular} \begin{tabular}{|c|c|} \hline\( x \) & \( y \) \\ \hline\( -6 \) & \( -30 \) \\ \hline\( -3 \) & \( -21 \) \\ \hline 0 & \( -12 \) \\ \hline 3 & \( -3 \) \\ \hline \end{tabular} What is the solution to this system? \( 0\left(-\frac{13}{1},-25\right) \) 0 \( \left(-\frac{14}{3},-54\right) \) \( (-13,-50) \) \( (-16,-54) \)

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