AIR MATH

Math Question

A bag contains 6 orange marbles and 7 green marbles. A marble is selected from the bag at random, set aside, and then another marble is selected. Which of the following choices correctly computes the probability that both marbles are orange? Select one: \( \frac{7}{13} \cdot \frac{6}{12}=\frac{7}{26} \) \( \frac{6}{13} \cdot \frac{5}{12}=\frac{5}{26} \) \( \frac{6}{13} \cdot \frac{5}{13}=\frac{30}{169} \) \( \frac{6}{13} \cdot \frac{6}{13}=\frac{36}{169} \)

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