AIR MATH

Math Question

A bacterium in a petri dish multiplies by a factor of 2 every day. On day 0 , there is 1 bacterium; on day 1, there are 2 bacteria; on day 2, there are \( 2 \cdot 2=4 \) bacteria; on day 3 , there are \( 2 \cdot 2 \cdot 2=8 \) bacteria, and so on. What logarithmic equation can be used to find the number of days it takes for a colony of \( 1,000,000,000 \) bacteria to develop?
A. \( 1,000,000,000 x=\log _{10} 2 \)
B. \( 1,000,000,000=\log _{2} \mathrm{x} \)
C. \( x=\log _{2} 1,000,000,000 \)
D. \( x^{2}=\log _{10} 1,000,000,000 \)

Solution

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